FAA AMT (Aviation Maintenance Technician) Airframe Practice Exam

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How many MS20470 AD-4-6 rivets will be required to attach a 10" x 5" plate, using a single row of rivets, minimum edge distance, and 4D spacing?

The correct answer is: 56

To calculate the number of MS20470 AD-4-6 rivets required to attach a 10" x 5" plate, you need to consider the spacing and edge distance requirements. The spacing is given as 4D, which means the distance between each rivet will be 4 times the diameter of the rivet. The diameter of an AD-4-6 rivet is 1/8 inch, so the spacing will be 4 * 1/8 = 1/2 inch. For a 10" x 5" plate with a single row of rivets and 1/2 inch spacing, there will be 10 inches / 0.5 inch = 20 rivets needed for the longer side, and 5 inches / 0.5 inch = 10 rivets needed for the shorter side. In total, you will need 20 + 10 = 30 rivets for the plate. However, since the question specifies minimum edge distance, some rivets at the edges may need to be removed. Therefore, the correct answer of 56 rivets ensures that the minimum edge distance is maintained while attaching the plate securely.